1,2(2,9) $42(No, that's incorrect. Try again.HINT: )$43($4255Notice that the b term is negative.)$44($4255The square of a negative number is a positive number. Check your calculations.)$45($4255Your answer is not reduced to loewst terms.)$46($4255Identify a, b, and c and insert the values into the quadratic formula. Check your work.) n(1=2)
Solve this equation using the quadratic formula.Separate the solutions with a comma. If there areno solutions type NONE.x2 - 3x + 4 = 0iT11Solve: x2 - 3x + 4 = 0a = 1, b = -3, c = 4px = -b Ü b2 - 4ac2ap+20Replace a, b, and c.x = -(-3) Ü 5 - 4(1)(4)2(1)p+20Simplify.x = 3 Ü 62pThe solutions are 1 and 2.
1,2,3(2,4) $42(No, that's incorrect. Try again.HINT: )$43($4255You have made a sign mistake with the b term.)$44($4255You may have reduced incorrectly. Check your work.)$45($4255Identify a, b, and c and insert the values into the quadratic formula. Check your work.)n(2f>1)
Solve this equation using the quadratic formula.4x2 - 6x + 10 = 0iT12Solve: 4x2 - 6x + 10 = 0a = 4, b = -6, c = 10px = -b Ü b2 - 4ac2ap+20Replace a, b, and c. x = 6 Ü 11 - 4(4)(10)2(4)pcsx = 6 Ü 11 - 4(4)(10)2(4)+20Simplify.x = 6 Ü 87p+20Simplify radical and reduce.x = 6 Ü 527p+20Factor.x = 5(1 Ü 2)(5)(3)p+20Reduce.x = 1 Ü 23The solutions are 1 + 23 and 1 - 23.
1 Ü 23-1 Ü 231 Ü 25No solution@@$43@$44@$45
1,2(5,15) $42(No, that's incorrect. Try again.HINT: )$43($4255Add 4 to both sides to write the equation in standard form.)$44($4255You may have cancelled incorrectly in the last step. Check your work.)$46($4255Write the equation in standard form and identify a, b, and c. Use the quadratic formula. Check.)
Solve this equation using the quadratic formula.Separate the solutions with a comma. If there areno solutions type NONE. #if(0=0)Use Ctrl-S to begin a radical and the right arrow to end it.#elseUse a \ to begin a radical and a ] to end it.#endifx2 - 3x = -4iT11aSolve: x2 - 3x = -4+20Add 4 to both sides.x2 - 3x + 4 = 0pa = 1, b = -3, c = 4px = -b Ü b2 - 4ac2ap+20Replace a, b, and c.x = 3 Ü 5 - 4(1)(4)2(1)pcsx = 3 Ü 5 - 4(1)(4)2(1)+20Simplify radicals and reduce.x = 3 Ü 62px = 3 Ü 282px = 2(7 Ü 8)2The solutions are 7 + 8 and 7 - 8.
1,2(2,9) $42(No, that's incorrect. Try again.HINT: )$43($4255Notice that the b term is negative.)$44($4255The square of a negative number is a positive number. Check your calculations.)$45($4255Your answer is not reduced to loewst terms.)$46($4255Identify a, b, and c and insert the values into the quadratic formula. Check your work.) n(1=2)
Solve this equation using the quadratic formula.Separate the solutions with a comma. If there areno solutions type NONE.x2 - 3x + 4 = 0iT11Solve: x2 - 3x + 4 = 0a = 1, b = -3, c = 4px = -b Ü b2 - 4ac2ap+20Replace a, b, and c.x = -(-3) Ü 5 - 4(1)(4)2(1)p+20Simplify.x = 3 Ü 62pThe solutions are 1 and 2.
1(6,9)12(1,2) $42(No, that's incorrect. Try again.HINT: )$43($4255Write the equation in standard form and identify a, b, and c. Use the quadratic formula. Check.)$44($4255You did not use the denominator, 2a, in the quadratic formula.)
Solve this equation using the quadratic formula.(x + 1)(x + 2) = 3iT12Solve: (x + 1)(x + 2) = 320Multiply both binomials on the left. x2 + 7x + 8 = 3p20Subtract 3 from both sides.5 x2 + 7x + 9 = 0pa = 1, b = 7, c = 9px = -b Ü b2 - 4ac2ap20Replace a, b, and c.x = -7 Ü 10 - 4(1)(9)2(1)pcsx = -7 Ü 10 - 4(1)(9)2(1)25Simplify.x = -7 Ü 52p25Simplify radical and reduce.x = -7 Ü 62x = 11 and 12The solutions are 11 and 12.
11, 1213, 1415, 16No solution@@$44@$43@$43
1,2,3(2,4) $42(No, that's incorrect. Try again.HINT: )$43($4255Identify a, b, and c and insert the values into the quadratic formula. Check your work.)n(2f>1)
Solve this equation using the quadratic formula.4x2 - 6x + 10 = 0iT12Solve: 4x2 - 6x + 10 = 0a = 4, b = -6, c = 10px = -b Ü b2 - 4ac2ap+20Replace a, b, and c.x = 6 Ü 11 - 4(4)(10)2(4)pcsx = 6 Ü 11 - 4(4)(10)2(4)+20Simplify.x = 6 Ü 87p+20Simplify radical and reduce.x = 6 Ü 527p+20Factor.x = 5(1 Ü 2)(5)(3)p+20Reduce.x = 1 Ü 23The solutions are 1 + 23 and 1 - 23.